Which of the following complexes is tetrahedr | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $1$. $[Ni(CN)_4]^{2-}$: $Ni^{2+}$ is $d^8$. $CN^-$ is a strong field ligand,causing pairing. It forms $dsp^2$ hybridization,which is square planar

Vedclass · Accepted Answer

$[Ni(CO)_4]$

Vedclass · Answer

(C) $1$. $[Ni(CN)_4]^{2-}$: $Ni^{2+}$ is $d^8$. $CN^-$ is a strong field ligand,causing pairing. It forms $dsp^2$ hybridization,which is square planar and diamagnetic.$2$. $[NiCl_4]^{2-}$: $Ni^{2+}$ is $d^8$. $Cl^-$ is a weak field ligand. It forms $sp^3$ hybridization,which is tetrahedral and paramagnetic.$3$. $[Ni(CO)_4]$: $Ni$ is $d^8s^2$. $CO$ is a strong field ligand,forcing electrons to pair. It forms $sp^3$ hybridization,which is tetrahedral and diamagnetic.$4$. $[Fe(CO)_5]$: $Fe$ is $d^6s^2$. It forms $dsp^3$ hybridization,which is trigonal bipyramidal and diamagnetic.Therefore,the complex that is both tetrahedral and diamagnetic is $[Ni(CO)_4]$.

List-$I$ (Complexes)	List-$II$ (Hybridisation)
$A$. $[Ni(CO)_4]$	$I$. $sp^3$
$B$. $[Cu(NH_3)_4]^{2+}$	$II$. $dsp^2$
$C$. $[Fe(NH_3)_6]^{2+}$	$III$. $sp^3d^2$
$D$. $[Fe(H_2O)_6]^{2+}$	$IV$. $d^2sp^3$

Which of the following complexes is tetrahedral as well as diamagnetic?

Similar Questions

How many number of unpaired electrons are there in the complex ion $[Ni(CN)_4]^{2-}$?

Which of the following hybrid states is associated with a low spin octahedral complex?

Match List-$I$ with List-$II$:

List-$I$ (Complexes) List-$II$ (Hybridisation)

$A$. $[Ni(CO)_4]$ $I$. $sp^3$

$B$. $[Cu(NH_3)_4]^{2+}$ $II$. $dsp^2$

$C$. $[Fe(NH_3)_6]^{2+}$ $III$. $sp^3d^2$

$D$. $[Fe(H_2O)_6]^{2+}$ $IV$. $d^2sp^3$

Which of the following is correctly matched?

What type of hybridization is involved in $[Fe(CN)_6]^{3-}$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module